DAYOFYEAR()
Description
Returns the day of the year for date, in the range 1 to 366.
Syntax
> DAYOFYEAR(expr)
Arguments
| Arguments | Description |
|---|---|
| expr | Required. The date to get the day from. Must be date type. |
Examples
drop table if exists t1;
create table t1(a date, b datetime,c varchar(30));
insert into t1 values('2022-01-01','2022-01-01 01:01:01','2022-01-01 01:01:01');
insert into t1 values('2022-01-01','2022-01-01 01:01:01','2022-01-01 01:01:01');
insert into t1 values(20220101,'2022-01-01 01:01:01','2022-13-13 01:01:01');
insert into t1 values('2022-01-02','2022-01-02 23:01:01','2022-01-01 23:01:01');
insert into t1 values('2021-12-31','2021-12-30 23:59:59','2021-12-30 23:59:59');
insert into t1 values('2022-06-30','2021-12-30 23:59:59','2021-12-30 23:59:59');
mysql> select distinct dayofyear(a) as dya from t1;
+------+
| dya |
+------+
| 1 |
| 2 |
| 365 |
| 181 |
+------+
4 rows in set (0.00 sec)
mysql> select * from t1 where dayofyear(a)>120;
+------------+---------------------+---------------------+
| a | b | c |
+------------+---------------------+---------------------+
| 2021-12-31 | 2021-12-30 23:59:59 | 2021-12-30 23:59:59 |
| 2022-06-30 | 2021-12-30 23:59:59 | 2021-12-30 23:59:59 |
+------------+---------------------+---------------------+
2 rows in set (0.01 sec)
mysql> select * from t1 where dayofyear(a) between 1 and 184;
+------------+---------------------+---------------------+
| a | b | c |
+------------+---------------------+---------------------+
| 2022-01-01 | 2022-01-01 01:01:01 | 2022-01-01 01:01:01 |
| 2022-01-01 | 2022-01-01 01:01:01 | 2022-01-01 01:01:01 |
| 2022-01-01 | 2022-01-01 01:01:01 | 2022-13-13 01:01:01 |
| 2022-01-02 | 2022-01-02 23:01:01 | 2022-01-01 23:01:01 |
| 2022-06-30 | 2021-12-30 23:59:59 | 2021-12-30 23:59:59 |
+------------+---------------------+---------------------+
4 rows in set (0.00 sec)
Constraints
DAYOFYEAR()only supports date type for now.- The date type supports only
yyyy-mm-ddandyyyymmddfor now.